Two liquids A and B have θ_ A and θ_ B as contact angles in a capillary tube. If K= θ_A / θ_B . then identify the correct statement:

Correct answer: C. K is negative, then liquid A has concave meniscus and liquid B has convex meniscus k= θ_ A θ_ B It is negative when θ_A \& θ_B are of opposite sign. so option (3)

JEE Main 20254 AprilMorning Shift

Exam: JEE Main
Year: 2025
Date: 4 April
Shift: Morning Shift
Subject: Physics
Chapter: Mechanical Properties of Fluids

JEE Main 2025 · 4 April · Morning Shift · Physics · Mechanical Properties of Fluids

Two liquids A and B have θ_ A and θ_ B as contact angles in a...

Two liquids A and B have

\theta_{\mathrm{A}}

and

\theta_{\mathrm{B}}

as contact angles in a capillary tube. If

K=\cos \theta_A / \cos \theta_B

. then identify the correct statement:

Options

A $K$ is negative, then liquid $A$ and liquid $B$ have convex meniscus.
B $K$ is negative, then liquid $A$ and liquid $B$ have concave meniscus.
CK is negative, then liquid A has concave meniscus and liquid $B$ has convex meniscus
DK is zero, then liquid A has convex meniscus and liquid B has concave meniscus.

Correct answer

C. K is negative, then liquid A has concave meniscus and liquid $B$ has convex meniscus

Step-by-step solution

\mathrm{k}=\frac{\cos \theta_{\mathrm{A}}}{\cos \theta_{\mathrm{B}}}

It is negative when

\cos \theta_A \& \cos \theta_B

are of opposite sign. so option (3)

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