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JEE Main 202524 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2025 · 24 January · Morning Shift · Physics · Mechanical Properties of Fluids

The amount of work done to break a big water drop of radius ' R '...

The amount of work done to break a big water drop of radius ' RR ' into 27 small drops of equal radius is 10 J . The work done required to break the same big drop into 64 small drops of equal radius will be

Options

  1. A15 J
  2. B5 J
  3. C20 J
  4. D10 J

Correct answer

A. 15 J

Step-by-step solution

W1=s4π(R3)2×27−4πR2⋅s⇒W1=4πR2⋅s(2)=10 Joule \begin{aligned} & W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \\ & \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text{ Joule } \end{aligned} Now, W2=s4πR2(4−1)=4πR2s×3⇒W2=3×102=15 Joule W_2=s 4 \pi R^2(4-1)=4 \pi R^2 s \times 3 \Rightarrow \quad W_2=3 \times \frac{10}{2}=15 \text{ Joule }
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