JEE Main202524 Jan 2025Morning ShiftPhysicsMechanical Properties of FluidsActual
The amount of work done to break a big water drop of radius ' R ' into 27 small drops of equal radius is 10 J . The work done required to break the same big drop into 64 small drops of equal radius will be
Options
- A15 J
- B5 J
- C20 J
- D10 J
Correct answer
A. 15 J
Step-by-step solution
aligned & W₁=s 4 ( R 3 )^2 27-4 R^2 s & W₁=4 R^2 s(2)=10 Joule aligned Now, W₂=s 4 R^2(4-1)=4 R^2 s 3 W₂=3 10 2 =15 Joule