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JEE Main202524 Jan 2025Morning ShiftPhysicsMechanical Properties of FluidsActual

An air bubble of radius 0.1 cm lies at a depth of 20 cm below the free surface of a liquid of density 1000 ~kg / m ^3 . If the pressure inside the bubble is 2100 ~N / m ^2 greater than the atmospheric pressure, then the surface tension of the liquid in SI unit is (use g =10 ~m / s ^2 )

Options

  1. A0.1
  2. B0.05
  3. C0.02
  4. D0.25

Correct answer

B. 0.05

Step-by-step solution

aligned & P₁=P₀+ g h=P₀+1000 10 20 100 & P₁=P₀+2000 aligned So, P₂-P₁= 2 S R = ( 2 S 1 10⁻³ ) P₂=P₀+2100 (given) aligned & So, P₀+2100-P₀-2000=2 S 10^3 & 100=2 S 10^3 & s= ( 1 20 )=0.05 aligned

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