JEE Main202127 Aug 2021Morning ShiftPhysicsMechanical Properties of FluidsActual
In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2 . 0 × 10 - 5 m and density 1 . 2 × 10 3 kg m - 3 ? Take viscosity of liquid = 1 . 8 × 10 - 5 N s m - 2 . (Neglect buoyancy due to air).
Options
- A5 . 8 × 10 - 10   N
- B3 . 9 × 10 - 10   N
- C1 . 8 × 10 - 10     N
- D3 . 8 × 10 - 11   N
Correct answer
B. 3 . 9 × 10 - 10   N
Step-by-step solution
Use the concept the viscous force is the same as the weight of the body, ⇒ F = m g = ρ × 4 3 π r 3 × g = 3 . 9 × 10 - 10   N .