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JEE Main 202126 AugustMorning Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Morning Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2021 · 26 August · Morning Shift · Physics · Mechanical Properties of Fluids

Two narrow bores of diameter 5 . 0mm and 8 . 0mm are joined...

Two narrow bores of diameter 5.0mmand8.0mm5 . 0mm and 8 . 0mm are joined together to form a U−U -shaped tube open at both ends. If this U−U -tube contains water, what is the difference in the level of two limbs of the tube.
[Take surface tension of water T=7.3×10−2Nm−1T = 7 . 3 \times {10}^{- 2}N{m}^{- 1}, angle of contact =0,g=10ms−2= 0, g = 10{ms}^{- 2} and density of water\left= 1 . 0 \times {10}^{3}kg{m}^{- 3}\right]Two narrow bores of diameter 5 . 0mm and 8 . 0mm are joined together to form a U - shaped tube open at both ends. If

Options

  1. A5.34mm5 . 34mm
  2. B3.62mm3 . 62mm
  3. C2.19mm2 . 19mm
  4. D4.97mm4 . 97mm

Correct answer

C. 2.19mm2 . 19mm

Step-by-step solution

Two narrow bores of diameter 5 . 0mm and 8 . 0mm are joined together to form a U - shaped tube open at both ends. If

P0−2TR1+h1ρg=P0−2TR2+h2ρg{P}_{0} - \dfrac{2T}{{R}_{1}} + {h}_{1}ρg = {P}_{0} - \dfrac{2T}{{R}_{2}} + {h}_{2}ρg
\left({h}_{1} - {h}_{2}\right)ρg = 2T\left[\dfrac{1}{2 . 5 \times {10}^{- 3}} - \dfrac{1}{4 \times {10}^{- 3}}\right] ⇒ {h}_{1} - {h}_{2} = 2 . 19mm

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