A hydraulic press can lift 100kg when a mass m is placed on the...

Using Pascals law,

$\dfrac{100 \times g}{{A}_{2}} = \dfrac{mg}{{A}_{1}} . . . \left(1\right)$

Let $m$ mass can lift ${M}_{0}$ in second case then

$\dfrac{{M}_{0}g}{16{A}_{2}} = \dfrac{mg}{{A}_{1} / 16} . . . \left(2\right)$

\left\{SinceA = \dfrac{\pi{d}^{2}}{4}\right\}$</p><p>From equation \left(1\right)$ and \left(2\right)$we get</p><p>$\dfrac{{M}_{0}}{16 . 100} = 16$</p><p>$⇒ {M}_{0} = 25600kg