A hydraulic press can lift 100 kg when a mass m is placed on the smaller piston. It can lift kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass m on the smaller piston.

Step-by-step solution

Using Pascals law, 100 × g A 2 = m g A 1                   . . . 1 Let m mass can lift M 0 in second case then M 0 g 16 A 2 = m g A 1 / 16                     . . . 2 Since   A = π d 2 4 From equation 1 and 2 we get M 0 16 . 100 = 16 ⇒ M 0 = 25600   kg