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JEE Main 20203 SeptemberMorning Shift

Exam: JEE Main
Year: 2020
Date: 3 September
Shift: Morning Shift
Subject: Physics
Chapter: Mechanical Properties of Fluids

JEE Main 2020 · 3 September · Morning Shift · Physics · Mechanical Properties of Fluids

When a long glass capillary tube of radius 0 . 015cm is dipped in a...

When a long glass capillary tube of radius

0 . 015cm

is dipped in a liquid, the liquid rises to a height of

15cm

within it. If the contact angle between the liquid and glass to close to

0 °

, the surface tension of the liquid, in milliNewton

{m}^{- 1},

is

\left[{ρ}_{\text{(liqued)}} = 900kg{m}^{- 3}, g = 10m{s}^{- 2}\right]

(Given answer in closed integer)

Correct answer

101

Step-by-step solution

Using the concept of rise due to surface tension,

$\dfrac{2T}{r} = hρg$

$T = \dfrac{rhρg}{2} = \dfrac{15 \times {10}^{- 5} \times 15 \times {10}^{- 2} \times 900 \times 10}{2} = 101milliNewton{m}^{- 1}$

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