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JEE Main 20202 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
2 September
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2020 · 2 September · Evening Shift · Physics · Mechanical Properties of Fluids

A capillary tube made of glass of radius 0 . 15mm is dipped...

A capillary tube made of glass of radius 0.15mm0 . 15mm is dipped vertically in a beaker filled with methylene iodide (surface tension =0.05Nm−1= 0 . 05N{m}^{- 1}, density =667kgm−3= 667kg{m}^{- 3}) which rises to height hh in the tube. It is observed that the two tangents drawn from observed that the two tangents drawn from liquid-glass interfaces (from opp. sides of the capillary) make an angle of 60º60 º with one another. Then hh is close to (g=10ms−2g = 10m{s}^{- 2})A capillary tube made of glass of radius 0 . 15mm is dipped vertically in a beaker filled with methylene iodide

Options

  1. A0.049m0 . 049m
  2. B0.087m0 . 087m
  3. C0.137m0 . 137m
  4. D0.172m0 . 172m

Correct answer

B. 0.087m0 . 087m

Step-by-step solution

h=2Tcosθρgrθ=30°P=667kgm−3;T=1/20Nm−1;r=0.15×10−3h = \dfrac{2Tcos\theta}{ρgr}\theta = 30 ° P = 667kg{m}^{- 3}; T = 1 / 20N{m}^{- 1}; r = 0 . 15 \times {10}^{- 3}

A capillary tube made of glass of radius 0 . 15mm is dipped vertically in a beaker filled with methylene iodide

=2×120×32667×10×0.15×10−3=0.087m= \dfrac{2 \times \dfrac{1}{20} \times \dfrac{\sqrt{3}}{2}}{667 \times 10 \times 0 . 15 \times {10}^{- 3}} = 0 . 087m

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