The increase in pressure required to decrease the volume of a water sample by 0.2 % is P 10^5 Nm ⁻² . Bulk modulus of water is 2.15 10^9 Nm ⁻² . The value of P is

Step-by-step solution

Since bulk modulus is given as aligned & B = - P ( ~V ~V ) & 2.15 10^9= - P - ( 0.2 100 ) & P =2.15 10^9 2 10⁻³ & =4.3 10^6=43 10^5 ~N / m ^2 aligned