Two persons pull a wire towards themselves. Each person exerts a force of 200 ~N on the wire. Young's modulus of the material of wire is 1 × 10^ 11 ~N ~m^ -2 . Original length of the wire is 2 ~m and the area of cross

Correct answer: 0 200 ~N O aligned & F A =Y (Δ )/( ) Δ = F AY & Δ = 200 × 2 2 × 10^ -4 × 10^ 11 =2 × 10^ -5 =20 μ m aligned

JEE Main 20249 AprilMorning Shift

JEE Main 2024 · 9 April · Morning Shift · Physics · Mechanical Properties of Solids

Two persons pull a wire towards themselves. Each person exerts a...

Two persons pull a wire towards themselves. Each person exerts a force of

200 \mathrm{~N}

on the wire. Young's modulus of the material of wire is

1 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}

. Original length of the wire is

2 \mathrm{~m}

and the area of cross section is

2 \mathrm{~cm}^2

. The wire will extend in length by ______

\mu \mathrm{m}

200 \mathrm{~N} \longleftrightarrow O

\begin{aligned} & \frac{\mathrm{F}}{\mathrm{A}}=\mathrm{Y} \frac{\Delta \ell}{\ell} \Rightarrow \Delta \ell=\frac{\mathrm{F} \ell}{\mathrm{AY}} \\ & \Delta \ell=\frac{200 \times 2}{2 \times 10^{-4} \times 10^{11}}=2 \times 10^{-5}=20 \mu \mathrm{m}\end{aligned}