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JEE Main202431 Jan 2024Morning ShiftPhysicsMechanical Properties of SolidsActual

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0 . 02 % is _____ m . (Take density of sea water = 10 3 kg m - 3 , Bulk modulus of rubber = 9 × 10 8 N m - 2 , and g = 10 m s - 2 )

Correct answer

0

Step-by-step solution

Bulk modulus is given by, B = - ∆ P ∆ V V ⇒ ∆ P = - B ∆ V V ⇒ ρ g h = - B ∆ V V ⇒ 10 3 × 10 × h = - 9 × 10 8 × - 0 . 02 100 ⇒ h = 18 m

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