An aluminium rod with Young’s modulus Y = 7 . 0 × 10 10 N m - 2 undergoes elastic strain of 0 . 04 % . The energy per unit volume stored in the rod in SI unit

Step-by-step solution

The data given is Y = 7 × 10 10   N   m - 2   and ∆ l l = 0 . 04 100 Young's modulus is given by the ratio of stress and strain, Y = F A ∆ l l = F l A ∆ l The energy stored is given as E = Y A 2 l ∆ l 2 ⇒ E = Y A 2 ∆ l l 2 × l       . . . ( i ) The energy per unit volume can be written from equation (i) E V = Y 2 × ∆ l l 2       . . . ( i i ) Substituting the values in equation (ii) E V = 1 2 × 7 × 10