A metal block of mass m is suspended from a rigid support through a metal wire of diameter 14 mm . The tensile stress developed in the wire under equilibrium state is 7 × 10 5 N m – 2 . The value of mass m is ______ kg . (Take g = 9 . 8 m s - 2 and π = 22 7 )

Step-by-step solution

The data given is T = 7 × 10 5   N   m - 2 r = 7 × 10 - 3   m Using the equation m g A = T ⇒ m g = T A ⇒ m g = T π r 2 ⇒ m g = 7 × 10 5 × 22 7 × 7 2 × 10 - 6 ⇒ m g = 49 × 22 10 ⇒ m = 49 × 22 98 = 11   kg