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JEE Main202229 Jun 2022Morning ShiftPhysicsMechanical Properties of SolidsActual

A wire of length L is hanging from a fixed support. The length changes to L 1 and L 2 when masses 1 kg and 2 kg are suspended respectively from its free end. Then the value of L is equal to

Options

  1. AL 1   L 2
  2. BL 1 + L 2 2
  3. C2 L 1 - L 2
  4. D3 L 1 - L 2

Correct answer

C. 2 L 1 - L 2

Step-by-step solution

From Hooke's law, ∆ L = F L A Y ⇒ ∆ L ∝ F . Therefore, L 2 - L L 1 - L = m 2 g m 1 g = 2 1 ⇒ L = 2 L 1 - L 2

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