JEE Main20202 Sep 2020Evening ShiftPhysicsMechanical Properties of SolidsActual
A wire of density 9 × 10 – 3 kg cm – 3 is stretched between two clamps 1 m apart. The resulting strain in the wire is 4 . 9 × 10 – 4 . The lowest frequency of the transverse vibrations in the wire (Young's modulus of wire Y = 9 × 10 10 Nm – 2 ), (to the nearest integer),_______
Correct answer
0
Step-by-step solution
Fundamental frequency in the string f = 1 2 ℓ T μ = 1 2 ℓ T ρA = 1 2 ℓ YΔℓ ρℓ f = 1 2 ℓ YΔℓ ρℓ = 1 2 9 × 10 10 × 4 . 9 × 10 - 4 9 × 10 - 3 × 10 - 6 = 35