JEE Main201910 Apr 2019Evening ShiftPhysicsMechanical Properties of SolidsActual
The elastic limit of brass is 379 M P a . The minimum diameter of a brass rod if it is to support a 400 N load without exceeding its elastic limit will be
Options
- A1.00 m m
- B1.36 m m
- C1.16 m m
- D0.90 m m
Correct answer
C. 1.16 m m
Step-by-step solution
Stress = F A Elastic limit is 379   M P a ⇒ 379 × 10 6 = 400 A = 400 π d 2 / 4 d = 400 × 4 π × 379 × 10 6 = 1.16 × 10 - 3   m = 1.16   m m