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JEE Main 201910 AprilEvening Shift

Exam: JEE Main
Year: 2019
Date: 10 April
Shift: Evening Shift
Subject: Physics
Chapter: Mechanical Properties of Solids

JEE Main 2019 · 10 April · Evening Shift · Physics · Mechanical Properties of Solids

The elastic limit of brass is 379MPa . The minimum diameter of a...

The elastic limit of brass is

379MPa

. The minimum diameter of a brass rod if it is to support a

400N

load without exceeding its elastic limit will be

Options

A $1.00mm$
B $1.36mm$
C $1.16mm$
D $0.90mm$

Correct answer

C. $1.16mm$

Step-by-step solution

Stress

= \dfrac{F}{A}

Elastic limit is

379MPa

⇒ 379 \times {10}^{6} = \dfrac{400}{A} = \dfrac{400}{\pi{d}^{2} / 4}

d = \sqrt{\dfrac{400 \times 4}{\pi \times 379 \times {10}^{6}}}

= 1.16 \times {10}^{- 3}m

= 1.16mm

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