JEE Main201910 Apr 2019Evening ShiftPhysicsMechanical Properties of SolidsActual
In an experiment, brass and steel wires of length 1 m each with areas of cross section 1 m m 2 are used. The wires are connected in series and one end of the combined wire is connected to a rigid support and other end is subjected to elongation. The stress required to produce a net elongation of 0.2 m m is, [Given, the Young's Modulus for steel and brass are, respectively, 120 × 10 9 N / m 2 and 60 × 10
Options
- A8.0 × 10 6 N / m 2
- B1.2 × 10 6 N / m 2
- C0.2 × 10 6 N / m 2
- D1.8 × 10 6 N / m 2
Correct answer
A. 8.0 × 10 6 N / m 2
Step-by-step solution
Stress will be same in both rods Stress = Y 1 Δ l 1 l = Y 2 Δ l 2 l … (1) And Δ l 1 + Δ l 2 = 0.2 × 10 - 3   m … (2) From equation (1) and (2) Stress × l Y 1 + l Y 2 = 0 .2 × 10 - 3   m Stress × 1 120 × 10 9 + 1 60 × 10 9 = 0.2 × 10 - 3   m Stress = 8 × 10 6   N / m 2