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JEE Main202315 Apr 2023Morning ShiftPhysicsMotion in One DimensionActual

The position of a particle related to time is given by x = ( 5 t 2 - 4 t + 5 ) m . The magnitude of velocity of the particle at t = 2 s will be :

Options

  1. A06   m   s - 1
  2. B14   m   s - 1
  3. C10   m   s - 1
  4. D16   m   s - 1

Correct answer

D. 16   m   s - 1

Step-by-step solution

It is given that x = 5 t 2 - 4 t + 5 The velocity is given by v = d x d t = d ( 5 t 2 - 4 t + 5 ) d t = 10 t   - 4   At t = 2   s , v = 10 ( 2 ) - 4 = 16   m   s - 1

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