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JEE Main 202313 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2023 · 13 April · Evening Shift · Physics · Motion in One Dimension

The distance travelled by an object in time t is given by s = (2 ....

The distance travelled by an object in time tt is given by s=(2.5)t2s = \left(2 . 5\right){t}^{2} . The instantaneous speed of the object att=5st = 5s will be :

Options

  1. A25ms–125m{s}^{– 1}
  2. B5ms–15m{s}^{– 1}
  3. C62.5ms–162 . 5m{s}^{– 1}
  4. D12.5ms–112 . 5m{s}^{– 1}

Correct answer

A. 25ms–125m{s}^{– 1}

Step-by-step solution

It is given that

s=2.5t2s = 2 . 5{t}^{2}

Differentiating,

v=dsdt=d(2.5t2)dt=5tv = \dfrac{ds}{dt} = \dfrac{d\left(2 . 5{t}^{2}\right)}{dt} = 5t

Att = 5s, v = 25m{s}^{- 1}

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