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JEE Main 20236 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2023 · 6 April · Evening Shift · Physics · Motion in One Dimension

A particle starts with an initial velocity of 10 . 0 ms ^ - 1 along...

A particle starts with an initial velocity of 10.0ms−110 . 0{ms}^{- 1} along xx-direction and accelerates uniformly at the rate of 2.0ms−22 . 0m{s}^{- 2}. The time taken by the particle to reach the velocity of 60.0ms−160 . 0m{s}^{- 1} is _____.

Options

  1. A25s25s
  2. B3s3s
  3. C6s6s
  4. D30s30s

Correct answer

A. 25s25s

Step-by-step solution

The given data is

v=60ms−1u=10ms−1a=2ms−2v = 60m{s}^{- 1}u = 10m{s}^{- 1}a = 2m{s}^{- 2}

Using the equation v=u+atv = u + at, we get

60=10+2t⇒t=(60−10)2⇒t=25s60 = 10 + 2t ⇒ t = \dfrac{\left(60 - 10\right)}{2} ⇒ t = 25s

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