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JEE Main20236 Apr 2023Evening ShiftPhysicsMotion in One DimensionActual

As shown in the figure, a particle is moving with constant speed π m s - 1 . Considering its motion from A to B , the magnitude of the average velocity is:

Options

  1. A3   m   s - 1
  2. Bπ   m   s - 1
  3. C1 . 5 3   m   s - 1
  4. D2 3   m   s - 1

Correct answer

C. 1 . 5 3   m   s - 1

Step-by-step solution

The given data is v = π   m   s - 1 By using trigonometric ratios in the triangle shown above the displacement can be found out by sin 60 ° = A B 2 R ⇒ A B = R 3 The formula for distance is d = v t ⇒ t = d v ⇒ t = 120 ° 360 ° × 2 π R π = 2 R 3 So, the average velocity is v avg = 3 R 2 R 3 = 3 3 2 = 1 . 5 3   m   s - 1

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