A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

Step-by-step solution

As the juggler is throwing n balls each second and 2 nd when the first is at its highest point, so the time taken by one ball to reach the highest point, t = 1 n   s . And as at highest point v = 0 . So, from first equation of motion, v = u + a t ⇒ 0 = u - g 1 n ⇒ u = g n Now in order to calculate height, using second equation of motion, we have: S = u t + 1 2 at 2 ...(i) ⇒ h = 1 n × g n - 1 2 g × 1 n 2 ⇒ h = g 2 n 2 So, the balls rise up to a height of h = g 2 n 2   m .