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JEE Main202131 Aug 2021Evening ShiftPhysicsMotion in One DimensionActual

A particle is moving with constant acceleration a . Following graph shows v 2 versus x (displacement) plot. The acceleration of the particle is _________ m s - 2 .

Correct answer

0

Step-by-step solution

The equation of the straight line, y = m x + c , from the above graph we get the equation, v 2 = 2 x + 20 , now differentiate it with respect to x , ⇒ 2 v d v d x = 2 ⇒ a = 2 2 = 1   m   s - 2 .

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