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JEE Main 202131 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2021 · 31 August · Evening Shift · Physics · Motion in One Dimension

A particle is moving with constant acceleration a . Following graph...

A particle is moving with constant acceleration a.a . Following graph shows v2{v}^{2} versus xx (displacement) plot. The acceleration of the particle is _________ ms−2.m{s}^{- 2} .
A particle is moving with constant acceleration a . Following graph shows v ^ 2 versus x (displacement) plot. The

Correct answer

0

Step-by-step solution

The equation of the straight line, y=mx+cy = mx + c, from the above graph we get the equation, v2=2x+20{v}^{2} = 2x + 20, now differentiate it with respect to xx,
⇒2vdvdx=2⇒a=22=1ms−2⇒ 2v\dfrac{dv}{dx} = 2 ⇒ a = \dfrac{2}{2} = 1m{s}^{- 2}.
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