Water drops are falling from a nozzle of a shower onto the floor...

For first drop.

$h = \dfrac{1}{2}g ( 2n{)}^{2}$

For ${2}^{\text{nd}}$ drop

${h}^{'} = \dfrac{1}{2}g ( n{)}^{2}$

$\dfrac{h}{{h}^{'}} = \dfrac{4}{1}$

${h}^{'} = \dfrac{h}{4} = \dfrac{9 . 8}{4}$

so height of ${2}^{nd}$ drop

$H = h - {h}^{'} = 9 . 8 - \dfrac{9 . 8}{4} = \dfrac{3}{4} \times 9 . 8 = 7 . 35m$