JEE Main202127 Aug 2021Evening ShiftPhysicsMotion in One DimensionActual
Water drops are falling from a nozzle of a shower onto the floor from a height of 9 . 8 m . The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.
Options
- A2 . 94   m
- B4 . 18   m
- C2 . 45   m
- D7 . 35   m
Correct answer
D. 7 . 35   m
Step-by-step solution
For first drop. h = 1 2 g ( 2 n ) 2 For 2 nd  drop h ' = 1 2 g ( n ) 2 h h ' = 4 1 h ' = h 4 = 9 . 8 4 so height of 2 nd   drop H = h - h ' = 9 . 8 - 9 . 8 4 = 3 4 × 9 . 8 = 7 . 35   m