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JEE Main202125 Jul 2021Evening ShiftPhysicsMotion in One DimensionActual

The relation between time t and distance x for a moving body is given as t = m x 2 + n x , where m and n are constants. The retardation of the motion is: (When v stands for velocity)

Options

  1. A2 m v 3
  2. B2 m n v 3
  3. C2 n v 3
  4. D2 n 2 v 3

Correct answer

A. 2 m v 3

Step-by-step solution

t = m x 2 + n x 1 v = d t d x = 2 m x + n V = 1 2 m x + n d v d t = - 2 m ( 2 m x + n ) 2 d x d t a = - ( 2 m ) v 3

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