Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4 th second after its fall to the next droplet is 34 . 3 m . At what rate the droplets are coming from the tap ? (Take g = 9 . 8 m s - 2 )

Step-by-step solution

In 4 th   sec , 1 st drop will travel ⇒ 1 2 × 9 . 8 × 4 2 = 78 . 4   m ∴   2 nd drop would have travelled ⇒ 78 . 4 - 34 . 3 = 44 . 1   m Time for 2 nd drop 1 2 9 . 8 t 2 = 44 . 1 t = 3   sec ∴ Each drop have time gap of 1   sec . ∴   1 drop per second.