Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202117 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
17 March
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2021 · 17 March · Morning Shift · Physics · Motion in One Dimension

A car accelerates from rest at a constant rate α for some time...

A car accelerates from rest at a constant rate α\alpha for some time after which it decelerates at a constant rate β\beta to come to rest. If the total time elapsed is t seconds, the total distance travelled is:A car accelerates from rest at a constant rate α for some time after which it decelerates at a constant rate β to come

Options

  1. A4αβ(α+β)t2\dfrac{4\alpha\beta}{( \alpha + \beta )}{t}^{2}
  2. B2αβ(α+β)t2\dfrac{2\alpha\beta}{( \alpha + \beta )}{t}^{2}
  3. Cαβ2(α+β)t2\dfrac{\alpha\beta}{2 ( \alpha + \beta )}{t}^{2}
  4. Dαβ4(α+β)t2\dfrac{\alpha\beta}{4 ( \alpha + \beta )}{t}^{2}

Correct answer

C. αβ2(α+β)t2\dfrac{\alpha\beta}{2 ( \alpha + \beta )}{t}^{2}

Step-by-step solution

A car accelerates from rest at a constant rate α for some time after which it decelerates at a constant rate β to come

v0=αt1{v}_{0} = \alpha{t}_{1} and 0=v0−βt2⇒v0=βt20 = {v}_{0} - \beta{t}_{2} ⇒ {v}_{0} = \beta{t}_{2}

t1+t2=t{t}_{1} + {t}_{2} = t

v0(1α+1β)=t{v}_{0}\left(\dfrac{1}{\alpha} + \dfrac{1}{\beta}\right) = t

⇒v0=α\betatα+β⇒ {v}_{0} = \dfrac{\alpha\betat}{\alpha + \beta}

Distance = area of v−tv - t graph

=12×t×v0=12×t×α\betatα+β=αβt22(α+β)= \dfrac{1}{2} \times t \times {v}_{0} = \dfrac{1}{2} \times t \times \dfrac{\alpha\betat}{\alpha + \beta} = \dfrac{\alpha\beta{t}^{2}}{2 ( \alpha + \beta )}

Practice Motion in One Dimension on Quantrex Academy →

More from Motion in One Dimension

A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a… JEE Main 2026Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12… JEE Main 2026The velocity ( v ) versus time ( t ) plot of a particle is shown in the figure, for a… JEE Main 2026From 18 m height above the ground a ball is dropped from rest. The height above the… JEE Main 2026Two cars A and B are moving in the same direction along a straight line with speeds 100… JEE Main 2026The velocity of a particle is given as v = -x i + 2y j - z k m/s. The magnitude of… JEE Main 2026A particle starts moving from time t=0 and its coordinate is given as x(t)=4 t^ 3 -3 t A.… JEE Main 2026Water drops fall from a tap on the floor, 5 m below, at regular intervals of time, the… JEE Main 2026 Full Motion in One Dimension list All JEE Main PYQs