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JEE Main 202116 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2021 · 16 March · Evening Shift · Physics · Motion in One Dimension

A mosquito is moving with a velocity → v = 0 . 5 t ^ 2 ^ i + 3t ^ j...

A mosquito is moving with a velocity \overset{\to}{v} = 0 . 5{t}^{2}\overset{^}{i} + 3t\overset{^}{j} + 9\overset{^}{k}m{s}^{- 1} and accelerating in uniform conditions. What will be the direction of mosquitoes after 2s2s ?

Options

  1. A\tan^{- 1}(23)\left(\dfrac{2}{3}\right) from xx-axis
  2. B\tan^{- 1}(856)\left(\dfrac{\sqrt{85}}{6}\right) from yy-axis
  3. C\tan^{- 1}(52)\left(\dfrac{5}{2}\right) from yy-axis
  4. D\tan^{- 1}(52)\left(\dfrac{5}{2}\right) from xx-axis

Correct answer

B. \tan^{- 1}(856)\left(\dfrac{\sqrt{85}}{6}\right) from yy-axis

Step-by-step solution

Given :
\overset{\to}{v} = 0 . 5{t}^{2}\overset{^}{i} + 3t\overset{^}{j} + 9\overset{^}{k}

\overset{\to}{v}att = 2 = 2\overset{^}{i} + 6\overset{^}{j} + 9\overset{^}{k}

∴∴ Angle made by direction of motion of mosquito will be,

cos⁡−1211\cos^{- 1}\dfrac{2}{11} (from xx-axis) =tan⁡−11172= \tan^{- 1}\dfrac{\sqrt{117}}{2}

cos⁡−1611\cos^{- 1}\dfrac{6}{11} (from yy-axis) =tan⁡−1856= \tan^{- 1}\dfrac{\sqrt{85}}{6}

cos⁡−1911\cos^{- 1}\dfrac{9}{11} (from zz-axis) =tan⁡−1409= \tan^{- 1}\dfrac{\sqrt{40}}{9}

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