A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [ g is the acceleration due to gravity]:

Step-by-step solution

⇒ For upward motion of helicopter v 2 = u 2 + 2 a s v 2 = 0 + 2 g h v = 2 g h ⇒ Now particle will start moving under gravity. s = u t + 1 2 a t 2 - h = 2 g h t - 1 2 g t 2 then t = 2 g h ± 2 g h + 4 × g 2 × h 2 × g 2 t = 2 g h g ( 1 + 2 ) t = 2 h g ( 1 + 2 )