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JEE Main 20204 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2020 · 4 September · Evening Shift · Physics · Motion in One Dimension

A particle of charge q and mass m is subjected to an electric field...

A particle of charge qandmassq and massmissubjectedtoanelectricfieldis subjected to an electric fieldE = {E}_{0}(1–ax2)\left(1 – a{x}^{2}\right) in the x−x -direction, where a and E0{E}_{0} are constants. Initially the particle was at rest at x=0x = 0. Other than the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is :

Options

  1. Aaa
  2. B2a\sqrt{\dfrac{2}{a}}
  3. C3a\sqrt{\dfrac{3}{a}}
  4. D1a\sqrt{\dfrac{1}{a}}

Correct answer

C. 3a\sqrt{\dfrac{3}{a}}

Step-by-step solution

Wex=ΔKK1−K1=0{W}_{ex} = \Delta K{K}_{1} - {K}_{1} = 0

∫0xqEdx=0{∫}_{0}^{x}qEdx = 0

q∫0xE0(1−Qx2)dx=0\text{q}{∫}_{0}^{x}{E}_{0}\left(1 - {Qx}^{2}\right)dx = 0

qE0∫0x(1−ax2)dx=0{qE}_{0}{∫}_{0}^{x}\left(1 - {ax}^{2}\right)dx = 0

x−ax33=0x - \dfrac{{ax}^{3}}{3} = 0

1−ax23=01 - \dfrac{{ax}^{2}}{3} = 0

ax23=1\dfrac{{ax}^{2}}{3} = 1

x2=3a{x}^{2} = \dfrac{3}{a}

x=3ax = \sqrt{\dfrac{3}{a}}

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