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JEE Main20208 Jan 2020Evening ShiftPhysicsMotion in One DimensionActual

A ball is dropped from the top of a 100 m high tower on a planet. In the last 1 2 s before hitting the ground, it covers a distance of 19 m . Acceleration due to gravity (in m s - 2 ) near the surface on that planet is______

Correct answer

0

Step-by-step solution

g t - 1 2 2 2 × 1 2 = 81 ... (1) 1 2 g t 2 = 100 …. (2) devide equation 1   &   2 t t - 1 2 = 10 9 t = 5   s put t in equation 2 g = 8   m s 2

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