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JEE Main 20208 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2020 · 8 January · Morning Shift · Physics · Motion in One Dimension

A particle is moving along the x -axis with its coordinate with...

A particle is moving along the xx -axis with its coordinate with time tt given by x(t)=10+8t−3t2.x\left(t\right) = 10 + 8t - 3{t}^{2} . Another particle is moving along the yy -axis with its coordinate as a function of time given by y(t)=5−8t3.y\left(t\right) = 5 - 8{t}^{3} . At t=1s,t = 1s, the speed of the second particle as measured in the frame of the first particle is given as v.\sqrt{v} . Then v(inms−1)v\left(inm{s}^{- 1}\right) is ___________.

Correct answer

0

Step-by-step solution

\overset{\to}{{v}_{1}} = \left(8 - 6t\right)\overset{^}{i}</p><p></p><p>\overset{\to}{{v}_{2}} = \left(- 24{t}^{2}\right)\overset{^}{j}</p><p>∣v21→∣=580</p><p>\left|\overset{\to}{{v}_{21}}\right| = \sqrt{580}

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