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JEE Main 20207 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2020 · 7 January · Evening Shift · Physics · Motion in One Dimension

An elevator in a building can carry a maximum of 10 persons, with...

An elevator in a building can carry a maximum of 1010 persons, with the average mass of each person being 68kg68kg . The mass of the elevator itself is 920kg920kg and it moves with a constant speed of 3m/s3m / s . The frictional force opposing the motion is 6000N6000N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g=10m/s2)\left(g = 10m / {s}^{2}\right) must be at least:

Options

  1. A56300W56300W
  2. B62360W62360W
  3. C48000W48000W
  4. D66000W66000W

Correct answer

D. 66000W66000W

Step-by-step solution

Net force on motor will be
Fm=[920+68(10)]g+6000{F}_{m} = \left[920 + 68\left(10\right)\right]g + 6000
=22000N= 22000N
So, required power for motor
Pm=F→m.v→{P}_{m} = {\overset{\to}{F}}_{m} . \overset{\to}{v}
=22000×3= 22000 \times 3
=66000watt= 66000watt
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