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JEE Main20207 Jan 2020Evening ShiftPhysicsMotion in One DimensionActual

An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 k g . The mass of the elevator itself is 920 k g and it moves with a constant speed of 3 m / s . The frictional force opposing the motion is 6000 N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator g = 10 m / s 2 must be at least:

Options

  1. A56300 W
  2. B62360 W
  3. C48000 W
  4. D66000 W

Correct answer

D. 66000 W

Step-by-step solution

Net force on motor will be F m = 920 + 68 10 g + 6000 = 22000   N So, required power for motor P m = F → m . v → = 22000 × 3 = 66000   w a t t

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