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JEE Main 201815 AprilMorning ShiftOnline

Exam: JEE Main
Year: 2018
Date: 15 April
Shift: Morning Shift
Mode: Online
Subject: Physics
Chapter: Motion in One Dimension

JEE Main 2018 · 15 April · Morning Shift · Online · Physics · Motion in One Dimension

An automobile, travelling at 40 ~km / h , can be stopped at a...

An automobile, travelling at

40 \mathrm{~km} / \mathrm{h}

, can be stopped at a distance of

40 \mathrm{~m}

by applying brakes. If the same automobile is travelling at

80 \mathrm{~km} / \mathrm{h}

, the minimum stopping distance, in metres, is (assume no skidding)

Options

A $75 \mathrm{~m}$
B $160 \mathrm{~m}$
C $100 \mathrm{~m}$
D $150 \mathrm{~m}$

Correct answer

B. $160 \mathrm{~m}$

Step-by-step solution

According to question,

u_1=40 \mathrm{~km} / \mathrm{h}, v_1=0

and

s_1=40 \mathrm{~m}

using

v^2-u^2=2 a s ; 0^2-40^2=2 a \times 40

..(i) Again,

0^2-80^2=2

as From eqn. (i) and (ii) Stopping distance,

s=160 \mathrm{~m}

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