The velocity-time graphs of a car and a scooter are shown in the figure. (i) the difference between the distance travelled by the car and the scooter in $15 \mathrm{~s}$ and (ii) the time at which the car will catch up with the scooter are, respectively

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The velocity-time graphs of a car and a scooter are shown in the figure. (i) the difference between the distance travelled by the car and the scooter in

15 \mathrm{~s}

and (ii) the time at which the car will catch up with the scooter are, respectively The velocity-time graphs of a car and a scooter are shown in the figure. (i) the difference between the distance

The velocity-time graphs of a car and a scooter are shown in the figure. (i) the difference between the distance

Quantrex Academy · Accepted Answer

Correct answer: C. 112.5 ~m and 22.5 ~s

Using equation, a=(v-u)/(t) and S=u t+ (1)/(2) a t² Distance travelled by car in 15 sec=(1)/(2) ((45))/(15)(15)^2=(675)/(2) ~m Distance traveled by scooter in 15 seconds =30 × 15=450( distance = speed × time ) Difference between distance travelled by car and scooter in 15 sec, 450-337.5=112.5 ~m Let car catches scooter in time t; (675)/(2)+45(t-15)=30 t337.5+45 t-675=30 t 15 t=337.5 t=22.5 sec

The velocity-time graphs of a car and a scooter are shown in the...

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