The velocity-time graphs of a car and a scooter are shown in the figure. (i) the difference between the distance travelled by the car and the scooter in 15 ~s and (ii) the time at which the car will catch up with the scooter are, respectively

Step-by-step solution

Using equation, a= v-u t and S=u t+ 1 2 a t^2 Distance travelled by car in 15 sec = 1 2 (45) 15 (15)^2= 675 2 ~m Distance traveled by scooter in 15 seconds =30 15=450( distance = speed time ) Difference between distance travelled by car and scooter in 15 sec , 450-337.5=112.5 ~m Let car catches scooter in time t; 675 2 +45(t-15)=30 t337.5+45 t -675=30 t 15 t =337.5 t =22.5 sec