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JEE Main2018PhysicsMotion in One DimensionActual

The velocity time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in 15 s and (ii) the time at which the car will catch up with the scooter are, respectively.

Options

  1. A112 . 5   m and 22 . 5   s
  2. B337 . 5   m and 25   s
  3. C225 . 5   m and 10   s
  4. D112 . 5   m and 15   s

Correct answer

A. 112 . 5   m and 22 . 5   s

Step-by-step solution

Distance travelled by car in 15   s = 1 2 × 45 × 15 × = 675 2   m . Distance travelled by scooter in 15   s = 30   × 15 = 450 . Let car catches scooter in time t difference between the distance travelled by car and scooter in 15   s in ⇒  450 − 675 2 = 112.5    m ⇒ 675 2 + 45 t - 15 = 30 t 337.5 + 45 t - 675 = 30 t     ⇒ 15   t = 337.5   ⇒ t = 22.5   s .

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