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JEE Main 202313 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Morning Shift
Subject
Physics
Chapter
Motion in Two Dimensions

JEE Main 2023 · 13 April · Morning Shift · Physics · Motion in Two Dimensions

A disc is rolling without slipping on a surface. The radius of the...

A disc is rolling without slipping on a surface. The radius of the disc is R.R . At t=0,t = 0, the top most point on the disc is AA as shown in figure. When the disc completes half of its rotation, the displacement of point AA from its initial position is

A disc is rolling without slipping on a surface. The radius of the disc is R . At t = 0, the top most point on the disc

Options

  1. A2R2R
  2. BR\sqrt{\left({\pi}^{2} + 4\right)}
  3. CR\sqrt{\left({\pi}^{2} + 1\right)}
  4. D2R\sqrt{\left(1 + 4{\pi}^{2}\right)}

Correct answer

B. R\sqrt{\left({\pi}^{2} + 4\right)}

Step-by-step solution

A disc is rolling without slipping on a surface. The radius of the disc is R . At t = 0, the top most point on the disc

The displacement is the hypotenuse of the diameter and the distance travelled for half the rotation \piR\piR.

By using Pythagoras theorem,

Displacement of A=(2R)2+(\piR)2A = \sqrt{( 2R{)}^{2} + ( \piR{)}^{2}}

=Rπ2+4= R\sqrt{{\pi}^{2} + 4}

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