The trajectory of projectile, projected from the ground is given by y = x - x 2 20 . Where x and y are measured in meter. The maximum height attained by the projectile will be.

Step-by-step solution

The trajectory of a projectile is parabolic in nature. At maximum height, it can be written that d y d x = 0       . . . 1 Substitute the expression for trajectory into equation (1) and solve to calculate the horizontal distance, for which the projectile attains the maximum height. d d x x - x 2 20 = 0 ⇒ 1 - x 10 = 0 ⇒ x = 10   m Substitute the value of x in the given expression for the trajectory to obtain the maximum height. y = 10 - 10 2 20   m =   5   m