JEE Main202330 Jan 2023Evening ShiftPhysicsMotion in Two DimensionsActual
A stone tied to 180 cm long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is 1936 x m s - 2 . The value of x ______. [Take π = 22 7 ]
Correct answer
0
Step-by-step solution
Angular velocity, ω = 28 × 2 π 60   rad   s - 1 . Required centripetal acceleration is given by, a = ω 2 R = 56 60 × 22 7 2 × 1 . 8 = ( 44 ) 2 225 × 1 . 8 = 1936 125 Hence, required x = 125 .