A boy ties a stone of mass 100g to the end of a 2m long string and whirls it around in a horizontal plane. The string can withstand the maximum tension of 80N . If the maximum speed with which the stone can revolve is

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Correct answer: C. 600

The maximum angular velocity of the stone is $\omega = rpm \times \dfrac{2\pi}{60} = \dfrac{K}{30}rad{s}^{- 1}$

The tension in the string will provide the required centripetal force. Therefore,

$T = m{\omega}^{2}l ⇒ 80 = 0 . 1 \times {\left(\dfrac{K}{30}\right)}^{2} \times 2 ⇒ {K}^{2} = 360000 ⇒ K = 600$

A boy ties a stone of mass 100g to the end of a 2m long string and...

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