Two blocks of masses m and M,(M m) , are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released then ( = coefficient of friction between the two blocks) (A) The time period of small oscillation of the two blocks is T =2 ( ~m + M ) k (B) The acceleration of the blocks is a = kx M + m ( x = displaceme

Step-by-step solution

(A) As both blocks moving together so Time period =2 ~m ~K ; where m = M + m T =2 M + m ~K (B) Let block is displaced by x in (+ ve ) direction so force on block will be in(-ve) direction aligned & F =- Kx & ( M + m ) a =- Kx & a =- Kx ( M + m ) aligned (C) As upper block is moving due to friction thus f = ma = mKx ( M + m ) (D) This option is like two block problem in friction for maximum amplitude, force on block is also maximum, for which both blocks are moving together. aligned & K A=(M+m) a & a= K A (M+m) & f=