JEE Main202524 Jan 2025Morning ShiftPhysicsOscillationsActual
A particle is executing simple harmonic motion with time period 2 s and amplitude 1 cm . If D and d are the total distance and displacement covered by the particle in 12.5 s , then D d is
Options
- A16 5
- B10
- C15 4
- D25
Correct answer
D. 25
Step-by-step solution
A = 1 cm aligned & n = 12.5 2 =6.25 cycles & D =4 6+1=25 & ~d =1 & D d =25 aligned