JEE Main20244 Apr 2024Evening ShiftPhysicsOscillationsActual
The displacement of a particle executing SHM is given by x=10 (w t+ 3 ) m . The time period of motion is 3.14 ~s . The velocity of the particle at t=0 is ______ m / s .
Correct answer
0
Step-by-step solution
Given, aligned & T =3.14= 2 & =2 rad / s & x =10 ( t + 3 ) & v = dx dt =10 ( t + 3 ) & at t =0 & v =10 ( 3 )=10 2 1 2 [ using =2 rad / s ] & v =10 ~m / s aligned