Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202313 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Morning Shift
Subject
Physics
Chapter
Oscillations

JEE Main 2023 · 13 April · Morning Shift · Physics · Oscillations

At a given point of time the value of displacement of a simple...

At a given point of time the value of displacement of a simple harmonic oscillator is given as y=Acos(30°).y = Acos\left(30 °\right) . If amplitude is 40cm40cm and kinetic energy at that time is 200J,200J, the value of force constant 1.0×10xNm–11 . 0 \times {10}^{x}N{m}^{– 1}. The value of xx is _____.

Correct answer

0

Step-by-step solution

The formula to calculate the kinetic energy (K)\left(K\right) of a particle executing SHM is given by

K=12k(A2−y2)...(1)K = \dfrac{1}{2}k\left({A}^{2} - {y}^{2}\right) . . . \left(1\right)

Substitute the values of the known parameters into equation (1) and solve to calculate the value of the unknown parameter.

{K=12×k×(A2−A2cos⁡230°)=12×k×A2sin⁡230°⇒200=12×1.0×10x×(0.4)2×(12)2=2×10x100⇒102=10x−2⇒x−2=2⇒x=4\begin{cases}K & = & \dfrac{1}{2} \times k \times \left({A}^{2} - {A}^{2}\cos^{2}30 °\right) \\ & = & \dfrac{1}{2} \times k \times {A}^{2}\sin^{2}30 ° \\ & ⇒ & 200 = \dfrac{1}{2} \times 1 . 0 \times {10}^{x} \times {\left(0 . 4\right)}^{2} \times {\left(\dfrac{1}{2}\right)}^{2} \\ & = & \dfrac{2 \times {10}^{x}}{100} \\ & ⇒ & {10}^{2} = {10}^{x - 2} \\ & ⇒ & x - 2 = 2 \\ & ⇒ & x = 4\end{cases}

Practice Oscillations on Quantrex Academy →

More from Oscillations

A tank contains two immiscible liquids of densities 6ρ and 2ρ . The higher density liquid… JEE Advanced 2026The frequency of oscillation of a mass m suspended by a spring is v_1 . If the length of… JEE Main 2026A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium… JEE Main 2026A particle is executing simple harmonic motion. Its amplitude is A and time period is 5… JEE Main 2026Match List-I with List-II. List-I List-II A. ^2 ω t I. Periodic with time period T =… JEE Main 2026A uniform disc of radius R and mass M is free to oscillate about the axis A as shown in… JEE Main 2026The velocity of a particle executing simple harmonic motion along x -axis is described as… JEE Main 2026The equation of motion of a particle is given by x = a (50t + (π)/(3)) cm. The particle… JEE Main 2026 Full Oscillations list All JEE Main PYQs