Choose the correct length ( L ) versus square of time period ( T _...

A simple pendulum consists of a point mass attached to an inextensible string and suspended from a support.

The formula to calculate the time period $\left(T\right)$ of a simple pendulum is given by

$T = 2\pi\sqrt{\dfrac{l}{g}} . . . . . . . . . . . . . . . . . . . . . . . ( 1 )$

where, $l$ is the length of the pendulum and $g$ is the acceleration due to gravity.

Simplify equation (1) to obtain the relation between the time period and the length.

$\begin{cases}{T}^{2} & = & \dfrac{4{\pi}^{2}}{g} \times 퓁 \\ {T}^{2} & ∝ & l . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( 2 )\end{cases}$

Equation (2) suggests that the graph between the square of the time period versus the length of the pendulum is a straight line passing through the origin.