A particle of mass 250g executes a simple harmonic motion under a...

Given, force $F = ( – 25x ) N$

$⇒ 0 . 25a = - 25x$

$⇒ a = - 100x$

Now comparing it with standard equation, $a = - {\omega}^{2}x$ we get

$\omega = 10$.

Now, {v}_\max = \omegaA

$⇒ \omegaA = 4$

$⇒ A = \dfrac{4}{10} = 0 . 4m$

$⇒ A = 40cm$.