JEE Main202224 Jun 2022Evening ShiftPhysicsOscillationsActual
Two massless springs with spring constants 2 k and 9 k , carry 50 g and 100 g masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be :
Options
- A3 : 2
- B1 : 2
- C3 : 1
- D2 : 3
Correct answer
A. 3 : 2
Step-by-step solution
Maximum velocity is given by v max = ω A = k m A Here, k 1 m 1 A 1 = k 2 m 2 A 2 ⇒ 2 k 50 × 10 - 3 A 1 = 9 k 100 × 10 - 3 A 2 ⇒ 2 A 1 = 3 A 2 Thus, ratio of amplitude is A 1 A 2 = 3 2 = 3 : 2 .