Y = Asin ( + ϕ _ 0 ) is the time-displacement equation of a SHM . At t = 0 the displacement of the particle is Y = (A)/(2) and it is moving along negative x -direction. Then the initial phase angle ϕ _ 0 will be:

Correct answer: C. (5π)/(6) Initial phase (π)/(2) + (π)/(3) = (5π)/(6) . Also it can be seen as below The initial phase angle ϕ _ 0 = π - (π)/(6) = (5π)/(6)

JEE Main 202125 FebruaryEvening Shift

Exam: JEE Main
Year: 2021
Date: 25 February
Shift: Evening Shift
Subject: Physics
Chapter: Oscillations

JEE Main 2021 · 25 February · Evening Shift · Physics · Oscillations

Y = Asin ( + ϕ _ 0 ) is the time-displacement equation of a SHM ....

Y = Asin

\left(\omegat + {ϕ}_{0}\right)

is the time-displacement equation of a

SHM .

t = 0

the displacement of the particle is

Y = \dfrac{A}{2}

and it is moving along negative

x

-direction. Then the initial phase angle

{ϕ}_{0}

will be:

Y = Asin ( + ϕ _ 0 ) is the time-displacement equation of a SHM . At t = 0 the displacement of the particle is Y =

Options

A $\dfrac{2\pi}{3}$
B $\dfrac{\pi}{6}$
C $\dfrac{5\pi}{6}$
D $\dfrac{\pi}{3}$

Correct answer

C. $\dfrac{5\pi}{6}$

Step-by-step solution

Y = Asin ( + ϕ _ 0 ) is the time-displacement equation of a SHM . At t = 0 the displacement of the particle is Y =

Initial phase $\dfrac{\pi}{2} + \dfrac{\pi}{3} = \dfrac{5\pi}{6}$ .

Also it can be seen as below

Y = Asin ( + ϕ _ 0 ) is the time-displacement equation of a SHM . At t = 0 the displacement of the particle is Y =

The initial phase angle ${ϕ}_{0} = \pi - \dfrac{\pi}{6}$
$= \dfrac{5\pi}{6}$

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