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JEE Main 20206 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Morning Shift
Subject
Physics
Chapter
Oscillations

JEE Main 2020 · 6 September · Morning Shift · Physics · Oscillations

An object of mass m is suspended at the end of a massless wire of...

An object of mass mm is suspended at the end of a massless wire of length LL and area of cross-section, A. Young modulus of the material of the wire is YY. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is :

Options

  1. Af=12πmLYAf = \dfrac{1}{2\pi}\sqrt{\dfrac{mL}{YA}}
  2. Bf=12πYAmLf = \dfrac{1}{2\pi}\sqrt{\dfrac{YA}{mL}}
  3. Cf=12πmAVLf = \dfrac{1}{2\pi}\sqrt{\dfrac{mA}{VL}}
  4. Df=12πYLmAf = \dfrac{1}{2\pi}\sqrt{\dfrac{YL}{mA}}

Correct answer

B. f=12πYAmLf = \dfrac{1}{2\pi}\sqrt{\dfrac{YA}{mL}}

Step-by-step solution

f=12πkm=12π(YAmL)f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} = \dfrac{1}{2\pi}\left(\sqrt{\dfrac{YA}{mL}}\right)

f=12πYAmLf = \dfrac{1}{2\pi}\sqrt{\dfrac{YA}{mL}}

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