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JEE Main20203 Sep 2020Evening ShiftPhysicsOscillationsActual

A block of mass m attached to a massless spring is performing oscillatory motion of amplitude 'A' on a frictionless horizontal plane. If half of the mass of the block breaks off when it is passing through its equilibrium point, the amplitude of oscillation for the remaining system become ƒA. The value of ƒ is:

Options

  1. A1 2
  2. B1
  3. C1 2
  4. D2

Correct answer

D. 2

Step-by-step solution

Using mometum conservation m 1 v 1 = m 2 v 2 m A ω = m 2 A 2 ω 2 m A k m = m 2 A 2 k m / 2 A 2 = 2 A ⇒ f = 2

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